Rams announce "guess our games" contest

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http://m.therams.com/s/30854/409?itemUri=40892409/14310414141210341021414812265

Fans May Enter at www.therams.com/guessourgamesthrough Friday, March 31

GOG-money-600.jpg


The Los Angeles Rams are launching the Guess Our Games contest, giving fans a chance to win one million dollars for correctly guessing the Rams 2017 schedule. Fans may visit www.therams.com/guessourgames to enter the contest through Friday, March 31.

In order to be eligible to win, a participant must properly identify each of the 16 Rams 2017 regular season games by picking the correct week of the NFL season and the day of week for each of the eight home and away contests. In addition, the Bye Week must be correctly selected.

Participants must be at least 18 years old to enter and only California residents are eligible to win. The contest is limited to one entry per person and email address.

ENTER HERE: GUESS OUR GAMES

Los Angeles Rams 2017 Regular Season Opponents

Home
Arizona Cardinals*
Houston Texans
Indianapolis Colts
New Orleans Saints
Philadelphia Eagles
San Francisco 49ers
Seattle Seahawks
Washington Redskins

Away

Arizona Cardinals
Dallas Cowboys
Jacksonville Jaguars
Minnesota Vikings
New York Giants
San Francisco 49ers
Seattle Seahawks
Tennessee Titans

*Game to be played in London at Twickenham Stadium
 
And as always, there is a 1 in a billion chance at guessing correct. YAY!!!
 
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It's actually 1 in (17! + 16! +15! + 14! + 13! + 12! + 11! +10! + 9! +8! + 7! + 6! + 5! + 4! + 3! + 2 + 1)


1 in 153?

naaa think its higher than that...much higher odds

each week there is a choice of Home, away, Monday Thursday or Sunday along with the bye week

so my math tells me 17 (weeks)x17 (opponents)x2(location) x3 (day)

I could be wrong...never did take a class on probability factors
 
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1 in 153?

naaa think its higher than that...much higher odds
I messed up the ! Factorial...

You Have a 1 in 17 chance of getting week 1 correct
Then you have a 1 in 16 change of getting week 2 correct
then you have a 1 in 15 chance of getting week 3 correct

They are ANDs so they are multiplied, so it's 17! (17 Factorial)
 
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I messed up the ! Factorial...

You Have a 1 in 17 chance of getting week 1 correct
Then you have a 1 in 16 change of getting week 2 correct
then you have a 1 in 15 chance of getting week 3 correct

They are ANDs so they are multiplied, so it's 17! (17 Factorial)


I have no idea what that means LOL
 
It's actually 1 in 355,687,428,096,000


Can you explain your math in laymans terms... I always like to learn new shit... being serious
 
Can you explain your math in laymans terms... I always like to learn new crap... being serious
The probability of getting week 1 correct is 1 in 17. 1/17
The probability of getting week 2 correct is 1 in 16 (only 16 weeks left and we got week 1 correct.) 1/16
Since we are calculating the odd of getting very week correct, we are using a mathematical AND as opposed to a mathematical OR.... and AND is multiplication

So the probability is 1/17 x 1/16 x 1/15 so on and so forth and is easily simple 1/17! (! means factorial)
so 6! = 6 x 5 x 4x 3 x 2 x 1

So in this case it's 1 in 17! ( 1 in 355,687,428,096,000 )
 
I'm gonna go out on a limb and predict Week 1 WILL NOT be the home game against the Cardinals.

Nostradumbass has spoken....
 
I can guarantee the Cardinals "home" game will be on October 22nd or 29th and the Bye week will be the week after.

No need to thank me, I'll just take a 5% cut of the prize when you win.
 
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Week one has to be the 9ers....has to be...2 new coaches....

That's a free one fellas from me....(y):yess::shades::snicker:
 
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Week one has to be the 9ers....has to be...2 new coaches....

That's a free one fellas from me....(y):yess::shades::snicker:

What are your other 15?... Should be a group collab. If 1 million is paid in full can split it to whom ever partakes. Would be awesome to know someone from ROD got it.
 
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The probability of getting week 1 correct is 1 in 17. 1/17
The probability of getting week 2 correct is 1 in 16 (only 16 weeks left and we got week 1 correct.) 1/16
Since we are calculating the odd of getting very week correct, we are using a mathematical AND as opposed to a mathematical OR.... and AND is multiplication

So the probability is 1/17 x 1/16 x 1/15 so on and so forth and is easily simple 1/17! (! means factorial)
so 6! = 6 x 5 x 4x 3 x 2 x 1

So in this case it's 1 in 17! ( 1 in 355,687,428,096,000 )


Thanks for the lesson..but wouldn't the odds be greater since you also have to correctly pick home and away and day of the week acording to the rules

Not trying to be a dick. .just asking
 
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Considering the FACT, I just noticed I Hit the "Powerball" last night for $165!:D I FEEL LUCKY!! (y)So I'm going to give it a Shot!!:mrburnsevil:
 
Thanks for the lesson..but wouldn't the odds be greater since you also have to correctly pick home and away and day of the week acording to the rules

Not trying to be a dick. .just asking
Considering the FACT, I just noticed I Hit the "Powerball" last night for $165!:D I FEEL LUCKY!! (y)So I'm going to give it a Shot!!:mrburnsevil:

All i got was the powerball... $4.
 
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Thanks for the lesson..but wouldn't the odds be greater since you also have to correctly pick home and away and day of the week acording to the rules

Not trying to be a dick. .just asking

Nope. Because Home and Away are already known.
So Arizona at LA (London) is 1 game and LA at Arizona is separate.
17 Unique Choices (16 Games and 1 Bye) But it's actually less because there would be no bye in week 1

So it's 16 x 16 ! So 1 in 334,764,638,208,000
 
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Nope. Because Home and Away are already known.
So Arizona at LA (London) is 1 game and LA at Arizona is separate.
17 Unique Choices (16 Games and 1 Bye) But it's actually less because there would be no bye in week 1

So it's 16 x 16 ! So 1 in 334,764,638,208,000

Don't you have to guess the correct day of the week (sun, mon, thurs) as well?
 
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BYE is usually week 8. Maybe they will throw a curve ball and we get a BYE week 1.